Integrand size = 20, antiderivative size = 149 \[ \int \frac {(a+b x)^3 (A+B x)}{(d+e x)^4} \, dx=\frac {b^3 B x}{e^4}-\frac {(b d-a e)^3 (B d-A e)}{3 e^5 (d+e x)^3}+\frac {(b d-a e)^2 (4 b B d-3 A b e-a B e)}{2 e^5 (d+e x)^2}-\frac {3 b (b d-a e) (2 b B d-A b e-a B e)}{e^5 (d+e x)}-\frac {b^2 (4 b B d-A b e-3 a B e) \log (d+e x)}{e^5} \]
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Time = 0.10 (sec) , antiderivative size = 149, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {78} \[ \int \frac {(a+b x)^3 (A+B x)}{(d+e x)^4} \, dx=-\frac {b^2 \log (d+e x) (-3 a B e-A b e+4 b B d)}{e^5}-\frac {3 b (b d-a e) (-a B e-A b e+2 b B d)}{e^5 (d+e x)}+\frac {(b d-a e)^2 (-a B e-3 A b e+4 b B d)}{2 e^5 (d+e x)^2}-\frac {(b d-a e)^3 (B d-A e)}{3 e^5 (d+e x)^3}+\frac {b^3 B x}{e^4} \]
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Rule 78
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {b^3 B}{e^4}+\frac {(-b d+a e)^3 (-B d+A e)}{e^4 (d+e x)^4}+\frac {(-b d+a e)^2 (-4 b B d+3 A b e+a B e)}{e^4 (d+e x)^3}-\frac {3 b (b d-a e) (-2 b B d+A b e+a B e)}{e^4 (d+e x)^2}+\frac {b^2 (-4 b B d+A b e+3 a B e)}{e^4 (d+e x)}\right ) \, dx \\ & = \frac {b^3 B x}{e^4}-\frac {(b d-a e)^3 (B d-A e)}{3 e^5 (d+e x)^3}+\frac {(b d-a e)^2 (4 b B d-3 A b e-a B e)}{2 e^5 (d+e x)^2}-\frac {3 b (b d-a e) (2 b B d-A b e-a B e)}{e^5 (d+e x)}-\frac {b^2 (4 b B d-A b e-3 a B e) \log (d+e x)}{e^5} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 232, normalized size of antiderivative = 1.56 \[ \int \frac {(a+b x)^3 (A+B x)}{(d+e x)^4} \, dx=\frac {-a^3 e^3 (2 A e+B (d+3 e x))-3 a^2 b e^2 \left (A e (d+3 e x)+2 B \left (d^2+3 d e x+3 e^2 x^2\right )\right )+3 a b^2 e \left (-2 A e \left (d^2+3 d e x+3 e^2 x^2\right )+B d \left (11 d^2+27 d e x+18 e^2 x^2\right )\right )+b^3 \left (A d e \left (11 d^2+27 d e x+18 e^2 x^2\right )-2 B \left (13 d^4+27 d^3 e x+9 d^2 e^2 x^2-9 d e^3 x^3-3 e^4 x^4\right )\right )-6 b^2 (4 b B d-A b e-3 a B e) (d+e x)^3 \log (d+e x)}{6 e^5 (d+e x)^3} \]
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Time = 0.69 (sec) , antiderivative size = 271, normalized size of antiderivative = 1.82
method | result | size |
norman | \(\frac {\frac {b^{3} B \,x^{4}}{e}-\frac {2 a^{3} A \,e^{4}+3 A \,a^{2} b d \,e^{3}+6 A a \,b^{2} d^{2} e^{2}-11 A \,b^{3} d^{3} e +B \,a^{3} d \,e^{3}+6 B \,a^{2} b \,d^{2} e^{2}-33 B a \,b^{2} d^{3} e +44 b^{3} B \,d^{4}}{6 e^{5}}-\frac {3 \left (A a \,b^{2} e^{2}-A \,b^{3} d e +B \,a^{2} b \,e^{2}-3 B a \,b^{2} d e +4 b^{3} B \,d^{2}\right ) x^{2}}{e^{3}}-\frac {\left (3 A \,a^{2} b \,e^{3}+6 A a \,b^{2} d \,e^{2}-9 A \,b^{3} d^{2} e +B \,a^{3} e^{3}+6 B \,a^{2} b d \,e^{2}-27 B a \,b^{2} d^{2} e +36 b^{3} B \,d^{3}\right ) x}{2 e^{4}}}{\left (e x +d \right )^{3}}+\frac {b^{2} \left (A b e +3 B a e -4 B b d \right ) \ln \left (e x +d \right )}{e^{5}}\) | \(271\) |
default | \(\frac {b^{3} B x}{e^{4}}-\frac {3 b \left (A a b \,e^{2}-A \,b^{2} d e +B \,a^{2} e^{2}-3 B a b d e +2 b^{2} B \,d^{2}\right )}{e^{5} \left (e x +d \right )}-\frac {a^{3} A \,e^{4}-3 A \,a^{2} b d \,e^{3}+3 A a \,b^{2} d^{2} e^{2}-A \,b^{3} d^{3} e -B \,a^{3} d \,e^{3}+3 B \,a^{2} b \,d^{2} e^{2}-3 B a \,b^{2} d^{3} e +b^{3} B \,d^{4}}{3 e^{5} \left (e x +d \right )^{3}}-\frac {3 A \,a^{2} b \,e^{3}-6 A a \,b^{2} d \,e^{2}+3 A \,b^{3} d^{2} e +B \,a^{3} e^{3}-6 B \,a^{2} b d \,e^{2}+9 B a \,b^{2} d^{2} e -4 b^{3} B \,d^{3}}{2 e^{5} \left (e x +d \right )^{2}}+\frac {b^{2} \left (A b e +3 B a e -4 B b d \right ) \ln \left (e x +d \right )}{e^{5}}\) | \(272\) |
risch | \(\frac {b^{3} B x}{e^{4}}+\frac {\left (-3 A a \,b^{2} e^{3}+3 A \,b^{3} d \,e^{2}-3 B \,a^{2} b \,e^{3}+9 B a \,b^{2} d \,e^{2}-6 b^{3} B \,d^{2} e \right ) x^{2}+\left (-\frac {3}{2} A \,a^{2} b \,e^{3}-3 A a \,b^{2} d \,e^{2}+\frac {9}{2} A \,b^{3} d^{2} e -\frac {1}{2} B \,a^{3} e^{3}-3 B \,a^{2} b d \,e^{2}+\frac {27}{2} B a \,b^{2} d^{2} e -10 b^{3} B \,d^{3}\right ) x -\frac {2 a^{3} A \,e^{4}+3 A \,a^{2} b d \,e^{3}+6 A a \,b^{2} d^{2} e^{2}-11 A \,b^{3} d^{3} e +B \,a^{3} d \,e^{3}+6 B \,a^{2} b \,d^{2} e^{2}-33 B a \,b^{2} d^{3} e +26 b^{3} B \,d^{4}}{6 e}}{e^{4} \left (e x +d \right )^{3}}+\frac {b^{3} \ln \left (e x +d \right ) A}{e^{4}}+\frac {3 b^{2} \ln \left (e x +d \right ) B a}{e^{4}}-\frac {4 b^{3} \ln \left (e x +d \right ) B d}{e^{5}}\) | \(290\) |
parallelrisch | \(\frac {-6 A a \,b^{2} d^{2} e^{2}-24 B \ln \left (e x +d \right ) x^{3} b^{3} d \,e^{3}+54 B \,x^{2} a \,b^{2} d \,e^{3}-18 A x a \,b^{2} d \,e^{3}-18 B x \,a^{2} b d \,e^{3}+81 B x a \,b^{2} d^{2} e^{2}+54 B \ln \left (e x +d \right ) x a \,b^{2} d^{2} e^{2}-44 b^{3} B \,d^{4}-2 a^{3} A \,e^{4}-B \,a^{3} d \,e^{3}+11 A \,b^{3} d^{3} e -3 A \,a^{2} b d \,e^{3}+54 B \ln \left (e x +d \right ) x^{2} a \,b^{2} d \,e^{3}+6 A \ln \left (e x +d \right ) x^{3} b^{3} e^{4}+18 B \ln \left (e x +d \right ) x^{3} a \,b^{2} e^{4}-6 B \,a^{2} b \,d^{2} e^{2}+33 B a \,b^{2} d^{3} e -18 A \,x^{2} a \,b^{2} e^{4}+18 A \,x^{2} b^{3} d \,e^{3}-18 B \,x^{2} a^{2} b \,e^{4}-72 B \,x^{2} b^{3} d^{2} e^{2}-9 A x \,a^{2} b \,e^{4}+27 A x \,b^{3} d^{2} e^{2}-108 B x \,b^{3} d^{3} e +6 A \ln \left (e x +d \right ) b^{3} d^{3} e +6 B \,x^{4} b^{3} e^{4}+18 B \ln \left (e x +d \right ) a \,b^{2} d^{3} e -3 B x \,a^{3} e^{4}-24 B \ln \left (e x +d \right ) b^{3} d^{4}+18 A \ln \left (e x +d \right ) x^{2} b^{3} d \,e^{3}-72 B \ln \left (e x +d \right ) x^{2} b^{3} d^{2} e^{2}+18 A \ln \left (e x +d \right ) x \,b^{3} d^{2} e^{2}-72 B \ln \left (e x +d \right ) x \,b^{3} d^{3} e}{6 e^{5} \left (e x +d \right )^{3}}\) | \(483\) |
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Leaf count of result is larger than twice the leaf count of optimal. 406 vs. \(2 (145) = 290\).
Time = 0.22 (sec) , antiderivative size = 406, normalized size of antiderivative = 2.72 \[ \int \frac {(a+b x)^3 (A+B x)}{(d+e x)^4} \, dx=\frac {6 \, B b^{3} e^{4} x^{4} + 18 \, B b^{3} d e^{3} x^{3} - 26 \, B b^{3} d^{4} - 2 \, A a^{3} e^{4} + 11 \, {\left (3 \, B a b^{2} + A b^{3}\right )} d^{3} e - 6 \, {\left (B a^{2} b + A a b^{2}\right )} d^{2} e^{2} - {\left (B a^{3} + 3 \, A a^{2} b\right )} d e^{3} - 18 \, {\left (B b^{3} d^{2} e^{2} - {\left (3 \, B a b^{2} + A b^{3}\right )} d e^{3} + {\left (B a^{2} b + A a b^{2}\right )} e^{4}\right )} x^{2} - 3 \, {\left (18 \, B b^{3} d^{3} e - 9 \, {\left (3 \, B a b^{2} + A b^{3}\right )} d^{2} e^{2} + 6 \, {\left (B a^{2} b + A a b^{2}\right )} d e^{3} + {\left (B a^{3} + 3 \, A a^{2} b\right )} e^{4}\right )} x - 6 \, {\left (4 \, B b^{3} d^{4} - {\left (3 \, B a b^{2} + A b^{3}\right )} d^{3} e + {\left (4 \, B b^{3} d e^{3} - {\left (3 \, B a b^{2} + A b^{3}\right )} e^{4}\right )} x^{3} + 3 \, {\left (4 \, B b^{3} d^{2} e^{2} - {\left (3 \, B a b^{2} + A b^{3}\right )} d e^{3}\right )} x^{2} + 3 \, {\left (4 \, B b^{3} d^{3} e - {\left (3 \, B a b^{2} + A b^{3}\right )} d^{2} e^{2}\right )} x\right )} \log \left (e x + d\right )}{6 \, {\left (e^{8} x^{3} + 3 \, d e^{7} x^{2} + 3 \, d^{2} e^{6} x + d^{3} e^{5}\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 337 vs. \(2 (143) = 286\).
Time = 5.90 (sec) , antiderivative size = 337, normalized size of antiderivative = 2.26 \[ \int \frac {(a+b x)^3 (A+B x)}{(d+e x)^4} \, dx=\frac {B b^{3} x}{e^{4}} + \frac {b^{2} \left (A b e + 3 B a e - 4 B b d\right ) \log {\left (d + e x \right )}}{e^{5}} + \frac {- 2 A a^{3} e^{4} - 3 A a^{2} b d e^{3} - 6 A a b^{2} d^{2} e^{2} + 11 A b^{3} d^{3} e - B a^{3} d e^{3} - 6 B a^{2} b d^{2} e^{2} + 33 B a b^{2} d^{3} e - 26 B b^{3} d^{4} + x^{2} \left (- 18 A a b^{2} e^{4} + 18 A b^{3} d e^{3} - 18 B a^{2} b e^{4} + 54 B a b^{2} d e^{3} - 36 B b^{3} d^{2} e^{2}\right ) + x \left (- 9 A a^{2} b e^{4} - 18 A a b^{2} d e^{3} + 27 A b^{3} d^{2} e^{2} - 3 B a^{3} e^{4} - 18 B a^{2} b d e^{3} + 81 B a b^{2} d^{2} e^{2} - 60 B b^{3} d^{3} e\right )}{6 d^{3} e^{5} + 18 d^{2} e^{6} x + 18 d e^{7} x^{2} + 6 e^{8} x^{3}} \]
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Time = 0.23 (sec) , antiderivative size = 284, normalized size of antiderivative = 1.91 \[ \int \frac {(a+b x)^3 (A+B x)}{(d+e x)^4} \, dx=\frac {B b^{3} x}{e^{4}} - \frac {26 \, B b^{3} d^{4} + 2 \, A a^{3} e^{4} - 11 \, {\left (3 \, B a b^{2} + A b^{3}\right )} d^{3} e + 6 \, {\left (B a^{2} b + A a b^{2}\right )} d^{2} e^{2} + {\left (B a^{3} + 3 \, A a^{2} b\right )} d e^{3} + 18 \, {\left (2 \, B b^{3} d^{2} e^{2} - {\left (3 \, B a b^{2} + A b^{3}\right )} d e^{3} + {\left (B a^{2} b + A a b^{2}\right )} e^{4}\right )} x^{2} + 3 \, {\left (20 \, B b^{3} d^{3} e - 9 \, {\left (3 \, B a b^{2} + A b^{3}\right )} d^{2} e^{2} + 6 \, {\left (B a^{2} b + A a b^{2}\right )} d e^{3} + {\left (B a^{3} + 3 \, A a^{2} b\right )} e^{4}\right )} x}{6 \, {\left (e^{8} x^{3} + 3 \, d e^{7} x^{2} + 3 \, d^{2} e^{6} x + d^{3} e^{5}\right )}} - \frac {{\left (4 \, B b^{3} d - {\left (3 \, B a b^{2} + A b^{3}\right )} e\right )} \log \left (e x + d\right )}{e^{5}} \]
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Time = 0.30 (sec) , antiderivative size = 279, normalized size of antiderivative = 1.87 \[ \int \frac {(a+b x)^3 (A+B x)}{(d+e x)^4} \, dx=\frac {B b^{3} x}{e^{4}} - \frac {{\left (4 \, B b^{3} d - 3 \, B a b^{2} e - A b^{3} e\right )} \log \left ({\left | e x + d \right |}\right )}{e^{5}} - \frac {26 \, B b^{3} d^{4} - 33 \, B a b^{2} d^{3} e - 11 \, A b^{3} d^{3} e + 6 \, B a^{2} b d^{2} e^{2} + 6 \, A a b^{2} d^{2} e^{2} + B a^{3} d e^{3} + 3 \, A a^{2} b d e^{3} + 2 \, A a^{3} e^{4} + 18 \, {\left (2 \, B b^{3} d^{2} e^{2} - 3 \, B a b^{2} d e^{3} - A b^{3} d e^{3} + B a^{2} b e^{4} + A a b^{2} e^{4}\right )} x^{2} + 3 \, {\left (20 \, B b^{3} d^{3} e - 27 \, B a b^{2} d^{2} e^{2} - 9 \, A b^{3} d^{2} e^{2} + 6 \, B a^{2} b d e^{3} + 6 \, A a b^{2} d e^{3} + B a^{3} e^{4} + 3 \, A a^{2} b e^{4}\right )} x}{6 \, {\left (e x + d\right )}^{3} e^{5}} \]
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Time = 1.33 (sec) , antiderivative size = 301, normalized size of antiderivative = 2.02 \[ \int \frac {(a+b x)^3 (A+B x)}{(d+e x)^4} \, dx=\frac {\ln \left (d+e\,x\right )\,\left (A\,b^3\,e-4\,B\,b^3\,d+3\,B\,a\,b^2\,e\right )}{e^5}-\frac {\frac {B\,a^3\,d\,e^3+2\,A\,a^3\,e^4+6\,B\,a^2\,b\,d^2\,e^2+3\,A\,a^2\,b\,d\,e^3-33\,B\,a\,b^2\,d^3\,e+6\,A\,a\,b^2\,d^2\,e^2+26\,B\,b^3\,d^4-11\,A\,b^3\,d^3\,e}{6\,e}+x\,\left (\frac {B\,a^3\,e^3}{2}+3\,B\,a^2\,b\,d\,e^2+\frac {3\,A\,a^2\,b\,e^3}{2}-\frac {27\,B\,a\,b^2\,d^2\,e}{2}+3\,A\,a\,b^2\,d\,e^2+10\,B\,b^3\,d^3-\frac {9\,A\,b^3\,d^2\,e}{2}\right )+x^2\,\left (3\,B\,a^2\,b\,e^3-9\,B\,a\,b^2\,d\,e^2+3\,A\,a\,b^2\,e^3+6\,B\,b^3\,d^2\,e-3\,A\,b^3\,d\,e^2\right )}{d^3\,e^4+3\,d^2\,e^5\,x+3\,d\,e^6\,x^2+e^7\,x^3}+\frac {B\,b^3\,x}{e^4} \]
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